(2y^2-3y-5)-(y^3-6y^2+5y)=0

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Solution for (2y^2-3y-5)-(y^3-6y^2+5y)=0 equation: 


Simplifying
(2y2 + -3y + -5) + -1(y3 + -6y2 + 5y) = 0

Reorder the terms:
(-5 + -3y + 2y2) + -1(y3 + -6y2 + 5y) = 0

Remove parenthesis around (-5 + -3y + 2y2)
-5 + -3y + 2y2 + -1(y3 + -6y2 + 5y) = 0

Reorder the terms:
-5 + -3y + 2y2 + -1(5y + -6y2 + y3) = 0
-5 + -3y + 2y2 + (5y * -1 + -6y2 * -1 + y3 * -1) = 0
-5 + -3y + 2y2 + (-5y + 6y2 + -1y3) = 0

Reorder the terms:
-5 + -3y + -5y + 2y2 + 6y2 + -1y3 = 0

Combine like terms: -3y + -5y = -8y
-5 + -8y + 2y2 + 6y2 + -1y3 = 0

Combine like terms: 2y2 + 6y2 = 8y2
-5 + -8y + 8y2 + -1y3 = 0

Solving
-5 + -8y + 8y2 + -1y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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